Problems based on days, years: Calendar based problems
This type of problems can be solved by understanding the below two pointers
1. A year has 365 days normally and 366 days in leap years.
That means 365/7= 52 weeks, Plus a 1 day(364 + 1)
Also
In leap years,
366/7= 52 weeks, plus 2 days (364+2)
2. Days repeat every 7 days. Rather every 7 days, day remains same. So divide a number of days with 7, if you get 0 as remainder, then the day is same. If you get 1 as remainder, day become plus one(example: Sunday becomes Monday) and so on.
Now
if
1st May 2010 is Saturday, what will be 1st may 2011
solution:
2010 is not a leap year (here 2010 being not leap year is not important, as February has already passed)
2011 is not a leap year( here 2011 being not a leap year is important, as February comes in our calculation)
What you have is 365 days between 1st May 2010 and 1st May 2011. That means 52 weeks and 1 day more.
Since 1st May 2010 is said to be Saturday, 1st may 2011 has to be Sunday.
But if the question had further asked about the day on 1st may 2012,what could be the answer?
You need to check whether 2012 is a leap year. Test for leap year, as you know, is divisible by 4 for years and divisible by 400 for centuries.
So you have a leap year in 2012.
So as stated before leap year involved will have 366/7=52 weeks plus 2 days.
So,
1st May 2012 will be Tuesday( Sunday + 2 days)
How to Prepare for Quantitative Aptitude
In problems with months difference between two dates instead of years, you have to the divide the number of days by 7, then take the extra days and add to the original.
While counting the number of days between two dates, bear in mind the following common mistakes
a. Don't count the two dates together. As in normal subtraction, the difference should exclude one of the dates
Like in
10-6=4
Count 9,8,7,6 can be 4 , correct
Count 10,9,8,7 can be 4, correct
But
10,9,8,7,6 is not equal to count 4, it gives 5, incorrect
b. Check whether the year is leap year. If yes, whether the months involve february.
This type of problems can be solved by understanding the below two pointers
1. A year has 365 days normally and 366 days in leap years.
That means 365/7= 52 weeks, Plus a 1 day(364 + 1)
Also
In leap years,
366/7= 52 weeks, plus 2 days (364+2)
2. Days repeat every 7 days. Rather every 7 days, day remains same. So divide a number of days with 7, if you get 0 as remainder, then the day is same. If you get 1 as remainder, day become plus one(example: Sunday becomes Monday) and so on.
Now
if
1st May 2010 is Saturday, what will be 1st may 2011
solution:
2010 is not a leap year (here 2010 being not leap year is not important, as February has already passed)
2011 is not a leap year( here 2011 being not a leap year is important, as February comes in our calculation)
What you have is 365 days between 1st May 2010 and 1st May 2011. That means 52 weeks and 1 day more.
Since 1st May 2010 is said to be Saturday, 1st may 2011 has to be Sunday.
But if the question had further asked about the day on 1st may 2012,what could be the answer?
You need to check whether 2012 is a leap year. Test for leap year, as you know, is divisible by 4 for years and divisible by 400 for centuries.
So you have a leap year in 2012.
So as stated before leap year involved will have 366/7=52 weeks plus 2 days.
So,
1st May 2012 will be Tuesday( Sunday + 2 days)
How to Prepare for Quantitative Aptitude
In problems with months difference between two dates instead of years, you have to the divide the number of days by 7, then take the extra days and add to the original.
While counting the number of days between two dates, bear in mind the following common mistakes
a. Don't count the two dates together. As in normal subtraction, the difference should exclude one of the dates
Like in
10-6=4
Count 9,8,7,6 can be 4 , correct
Count 10,9,8,7 can be 4, correct
But
10,9,8,7,6 is not equal to count 4, it gives 5, incorrect
b. Check whether the year is leap year. If yes, whether the months involve february.
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